Datasheet LT1364, LT1365 (Analog Devices) - 9

LT1364/LT1365
W U TYPICAL PERFORMANCE CHARACTERISTICS Small-Signal Transient Small-Signal Transient Small-Signal Transient (AV = 1) (AV = –1) (AV = –1, CL = 200pF)
1364/1365 TA31 1364/1365 TA32 1364/1365 TA33
Large-Signal Transient Large-Signal Transient Large-Signal Transient (A (A (A V = 1) V = – 1) V = 1, CL = 10,000pF)
1364/1365 TA34 1364/1365 TA35 1364/1365 TA36
U U W U APPLICATIONS INFORMATION Layout and Passive Components Input Considerations
The LT1364/LT1365 amplifiers are easy to use and toler- Each of the LT1364/LT1365 inputs is the base of an NPN ant of less than ideal layouts. For maximum performance and a PNP transistor whose base currents are of opposite (for example, fast 0.01% settling) use a ground plane, polarity and provide first-order bias current cancellation. short lead lengths, and RF-quality bypass capacitors Because of variation in the matching of NPN and PNP beta, (0.01µF to 0.1µF). For high drive current applications use the polarity of the input bias current can be positive or low ESR bypass capacitors (1µF to 10µF tantalum). negative. The offset current does not depend on NPN/PNP beta matching and is well controlled. The use of balanced The parallel combination of the feedback resistor and gain source resistance at each input is recommended for setting resistor on the inverting input combine with the applications where DC accuracy must be maximized. input capacitance to form a pole which can cause peaking or oscillations. If feedback resistors greater than 5kΩ are The inputs can withstand transient differential input volt- used, a parallel capacitor of value ages up to 10V without damage and need no clamping or source resistance for protection. Differential inputs, how- CF > RG x CIN/RF ever, generate large supply currents (tens of mA) as should be used to cancel the input pole and optimize required for high slew rates. If the device is used with dynamic performance. For unity-gain applications where sustained differential inputs, the average supply current a large feedback resistor is used, CF should be greater will increase, excessive power dissipation will result and than or equal to CIN. the part may be damaged.
The part should not be used as
9